報日橋
頁二第張三第日七初月五年辛夏 WAH KIU YAT PO
英中會考數學A(三)試題
CHONG KONG
CERTIFICATE OF EDUCATION EXAMINATION ERILISH›
Candides
cenù sảy, CHRIE quietions I Secto
manse di Centre
The, given diagrami sic hại necessary stáwn to acum
SECTION (40)
For questions para “the box opponteto in portaci andai ana or questions - par zie Answer if the spaces provided on the question papei Thị question papima muso de canded in any working chày th suonering the Jaar bew pages of the unjwer Booster wil dor de cucina Quartum mið)' uiouta be dona a The beginning of your shower boor
47 markar
490) is any triangle, it's point X ta equidumuri trompa una Cana meno equatiini trom Al-qadi
To'ché intersection of
the check ventre Bad NO THE DUNCIÓT DELACA
The-crete în 10 is drumeter and the bouctos of LAGA:
use perpendicular duectors of AC, una DC-
the perpendicular "busctor of AC. and the bisector of LACE.
the Diaectors of LBCAMS LBAC
(7 marks]
gure 1.
which one of the following statements mGAT
00000
1971英文中學會考試題預習專欄
日期星 日卅月五年一七九一三公年十六國民雄中,有致僑犟
(11) When ammonia is passed over hooted copper oud,
Colourless liquid and a colourless gas, drops of a
±& SUNLIGHT PRESS
化學科 (十九)
CHEMISTRY
LESSON TWENTY-NINE
A reducing agent is a substance which brings about an increase in the proportion of the electropositive component of the substance, for instance by adding hydrogen or by removing oxygen or any other electrone~ gative element or radical such as chlorine or sulphate
(b) (1) A slow stream of dry hydrogen is passed through a horizontal test tube containing a layer of black. copper oxide, and is lit at a small hole at the end of the tube after the air has been displaced. When the tube is heated gently, the oxide glows red hot and changes colour rapidly to the red colour typical of actallic copper. Steam escapes from the hole and extinguishes the hydrogen flame.
+ CuO » Cu + H
Since hydrogen has removed the oxygen from copp
oxide and thus acted as a reducing
英中會考數學A(二)答案
MA PREMA FICS SYLLABUS
PATULL) {Cóntinued)
reddish-brown residue are produced; The pit can be identified as nitrogen by burning magnem um in it
and adding water co the residue, when aponta will be evolved. The liquid, which turns anhgirout copper- sulphate blue, is water, and the residue must be
* NA. 2013
Ammonia has acted as a reducing agent because it hab removed oxygen: from copper oxide.
Hydrogen chloride acts as a reducing agent, when si the form of hot concentrated hydrochlorideid:it removes half the oxygen from manganese diorite in the preparation of chlorine. The manganese monoxide foratu fs immediately neutralised by excess hydrochloric acid
2HC1 • MÃO MD + 1,0 + €1.
20140 MIC
(iv) When hydrogen sulphide is passed through yellow..
ferric chloride solution, the solution becomes clouay due to the formation" of finely divided sulphur, on heating, the sulphur coagulates, and a pale green solution of ferrous chloride is obtained:
28C1
+
In this reaction hydrogen Gulphide acts as a reducing agent because in the ferrous chloride which as formed. the proportion of the electropositive component iron is higher than in the original ferric chloride.
SABC
Mora
an the centre of cache ÄBEL
Penguins, "bantajon
00000
mi rigure 5.100's the d'ameter of a circle and
48 "la #chon parallel to DC W Cosicolate CB(D
marker
figure o de circles whose centrem an "B" and
couch each ninay and placi vouch carer santr *.internally (AZADƏN GVAČ •Nim, and
mour to the
'ATAWIŁ, LEAD •
48 a partiler to CD OF WOD = 14 an. Gable am and CD • •'an: Caieutia cha
SABU
A dienen perpendacular uni
izioni Of · produced ni, é Cascurate, LAEI,
́ooing
SECTION
160 கூ
TURSKAS, ALOpe in, the, segumeni munde gran.
presentation' av materjal
Scharwan stat
stasis will "ba: sequcted for poor
in Figure was squad Sticles altérsaçlar in so
w's stringere une austing "ZLE GAME AN
Địcha thelatheist € ..
- polár
е
ngureni vransversal: yo "zuti sa paraber
sincer (ste, drawn in sauch each sluse chrea tubes as shown the diagram – Prova PORS
(1) ke
and
comparing:
i) the required
Let
and C be the roots of the equatio
then the roots of the new equation will be
pne g
-
applying the Sine FormALLS SALIB
Sán ADB
0.3711
ADB
-23:47
BDE
LABD
BE
70 Ain BOE
Area of the
130
801:
0.6186 sq. em.
The
rise of wate
(3850
Figure 10-PX acu·LOPR and PY bisects RPS. Ma the mud-point of XY
figure
Haric
Pues on the circle diameter XY Fatherwe prove that
(a) In CABO,
Bor
listine
din 30°
(11) for only one triangle,
His right-angled [1110 o triangle will
(b) By using the Cosine Formu
for MABEY
Cos BAC
BAC
Cog CAD
/CAD r
Therefore
Zsınë - ♬ sin 8.
2sin e
sinetz •/3)
1.2se
¿sin
Sin
The required
Cat 37°
AB
0.8660
Figure
rectangles.
LAPR
1500 Cor 679;
1500 col ?
bmarks!
KBCD 15 « trapezium with parallel to DC. Share the mid-points of BC AC
BD and AD respectway Prove that PQ =
shai PORS 18 e injoki lina
412 marks)
Pin, figure à 178C EF and De ara parallel
8. LDA
If the was of GALE la i squar unit' calculati
(i) the arts of ABEC
(the stop of GEAF
(9 márks)
to figure 12. ARB is avare of a circis radius
QA OB PO·ure cangonta a 48 wid
пересечнит ¿POO
00 cm
(i) Fund PQ us resma në
190°: PO
Hence otherwise and the raise of
fal 14 marks)
DOCF, é mediana-
“prove (hai, SABC, a moscales-
19 marks)
APR
ing
spot.
#point Inside the circ
the circle and, Prove that
tre on the same site of
CARR
mangle inscribed in
nice the angle bisectos al angles 46 and
kerter
and niest the oppoute aris WT
19 markat
DE CONTINUED)
figurë
Page 10Page 11