ERENCE
育教僑華莫三第張六第日九初月五年戌庚屬要 WAH Khi VAT 報日僑筆 英中會考現代數學(二)答案 ·高鑽獎。
HALL T-PO
五期星日二十月六年〇七九一曆公年九十五民警中
中中會考高級數學(一)試
本科因不在本報會考補習專攔範霋之內,故並無出答案,現豪亞洲 文化學売高鏡葵先生義務代答,雍惠選考該科之間學匪样,謹此致。
(兩小時光
FICAT
PICUTE
3x+4+5=50p
吳中會考現代数()答案
К к ко
Stup Key. .
若p為任意實數,求,
『之最小借
HK CERTIFICATE OF EDUCATION EXAMINATION
I REAA??2+as+1=02#Ro· 8; 5 IK 2+1
02 #
只邁英文書院電訊工程溉管馬嘉荣报:上有一校監林與銅紙園。《上左,校長陸永炮報告赘
1970
MATHEMATICS SYLLABUS B PAPER I
Find the 2x2 Matrix A such that
A ( 2 2 ) [ ( ? ? ) + ( 6 =))] = (! ;)
(b) Find x, y and z such that
(89)-(649)
lution
(4) A (5)-(!?)
A- (45) - (++) 2.HS=( 108 day boy)
Find the locus in the I-y plane so that the
tistance of each point of the locus from (2,5)
is equal to its distance from the line Ly
{(x, y) y+2=0; x, y ER}.
z Ziÿ
Find the intersection of the line 60=1127, y}
X,YER} and the locus.
What is the geometrical meaning of your resuel
Find also the line passing through the
and perpendicular to the given lin
Solution
Let p (x, y) be a point
on the locus
1 = √(x-2)2 + (y-3)*
dad
(given)
d (2-2)2 + (y-3)2 = y + z
(2,3)
pexy)
⇒ 22-4x+100+9=0 ( lowes)
{ 2 == 24 107 +9=0
5.5. { x=7;y=3} (point of intersection)
(Da2 +2+2 +8 21
(1):分解30~31至+101-x您光
5 21
30-31 10! —r
爲部份分式,並は、之!課題問之以求。
之係數。並派出此問式和之允許值之界限
某幾何殺數之公比圈,其慈項焉首痕的C倍
Blog
3.000.000
log C
(j)某城市人口每年依幾何級數培加。該城入口在1965年時屨
,在1970年時推至3600,000,求精嬷间級數之公
816371975 THARLAD
已知{}
+8
(f) 證明f(x)恒小於岁,
(ii)求,集之界阻便!)<2
(六)(g):x ] 解方程式:
V3x-3+ log; √x-1=2
(5)利用數學歸納法證明當n為正整數時,
1月篱13之倍數。
{5},同學9人旅行,分乘大小汽車各一端,大車最多可載个人,
矗多可載4人。求分親之辦法有顯示
J - £OZAHMABCD EF GHAE BF
HD各7cm,其他各邊均4cm。今使長方鐵之對角線AGA地面 垂邐而A在地上,
il E · F · G · H&RROZA.
1. THAB PLERIMIZZA »
(九)證明tan(一年)
KB tan (~+ * } – tam t
(十) 瓦輸出下列兩方程式之圖線
cos
~2810 (+3)
並利用該兩圖線解方程式
cos 3 sifs -com a
AM-1-(1)2-12 in
-ABC-
中中會考化學科答案(練 ) 林錫衡·
X203
XH3.
HXO3
XH3是還原田×所表現的氧化數在各 種化合物中最小當進行氧化還原作用時 其氧化數只可能增高無可減低即本身氧 化故為還原劑。
HXO是氧化形因×所表現的氧化数在谷 種化合物中最大當進行氧化原作用時 其氧化數只可能降低無可增高即本身還 原故為氧化劑。
還原作用例
亞硫酸溶液
5 H 2 SO 3 + 2 KMnO4 » K2SO4 + 2 MASOR
+ & H2 5 Q x + 3 HO
(i)氣化亞鐵溶液
求在0與2元關之債
1 mid-pl. theorem
AM-AN-22 ‚MN-₫
refer to A ABC
C-ICH-Z
uper to A OAH
2 FeCl + Ck → z Fecla
(ii)亞硝酸鉀溶液
5 KNO2+ ZKMnO4 + 3H2SOK
SKNO2+ K SQ2+2M#501+3H:0
A是硝酸鉛
B是硫酸鋅
C是硫酸鉛
D是二氧化
G. 是硫酸鋇
E是氧化鉛
F是硫化鉾
Pb(NO3)2 + ZnSO4 →→ Zn(NO3); + PbSOù &
2 P60+ANO2↑t QT
(2)Z Pb(NO3)2
(3) P6O+ZHND, Pb(NO3)[557%) + H2O (4) PbO+ H2SO2 →→→ Pb SOL (**) + HC (5) H25 + £n SO4 H2SO+ ZAS
(6) Zn50, + Ba(NO3) → Zn (NO3), + BaSON!
the locu
parabola and cuts y=x-4 at
one point.
slope of yox-4 10/
x+y=5 (neguired)
ABC is an equilateral
A. AO is I to the plane
Cano-714
Its angle between the planes ABC
(1) Evaluate Si. Sz and S. from the following glow
chart (START)
Read not
[ Tn == Ta-1 }
陰極
(6)
陽極
(鉑)
ABC M, N are mid-points.
of OC, OB respectively
If M (AB)= M (AO) - 1 inch, then
(8) Calculate the measure of the sides of DAMN,
(b) Calculate the measure of the angle in degrees
between the planes ABC and OBC.
Solution
(a) refer to A OAC
Increasi
n by ans
Record Sa
→STOP
The sum of the digits of in two digit number
of base 8 is 108. The number formed by
reversing the digits
by 168 Find the number.
7, - 2 % -2 2-1. 5-
the number
解
富童為 1,008
稀硫酸
一克當量 在 NTP 時枯
2.8升合法克當量=克當量
在硫酸亞鐵槽中魔得鐵
•克當量=x雙克 =2克
在硫酸鐵槽中應得鐵
56
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