愛上滋味
侯患者 潄,香
是阻隸 該有而選
二期星6日七十月三年〇七九一曆公年九十五國民華中 育僑華
定
天
頁二第張六第 日十初月二年戌庚夏
WAH KIU YAT PO
報日僑華
有矩
八主敎大專聯會討論
香港應否設
第三間大學
仕,百係之八十六是外來人材。
·近褡勁字指出:曹受大歷或工業學院動會的A
陳佐舜
主人發 意見。 : 士、陳一新及陳佐舜四 非強納斯人的被同,如何種布波大學以後的 嚴元帝博士、譚維漢博 一 大門,面對的難題,有發不少。聲如,如 | 公灏大怒約地方,不過,照說回來,要建立 「是必須的,關乎當今讀彩,香港是最適宜於建立 「公級換些需有掛港難,所以公發大學的設立 一流好娩何日响下的熱情神;摸他到說些, 這種的問題,都是帶我們大家的
今埏一個失落的世代,公秒學生可抛本身做起! 【明主的存在,更要負起傳料前用的大任。况且現
龙持查不
【開大學」由五位社會知名人士主袂演講 : 日舉行一項座談會,主題儂一本應否開辦第三 《韓凯、香港天主豹大喜師會教育委員會,本屆校際音樂及朗誦節
「隱刋述得。
「範大學問題」,所述如下:
家樊何璧‧要
朗誦樂評 後感
新
何沛雄
一设中擯頦有進步
领元素博士以題爲香 辛,今年中文朗誦比賽無盡成演,本人不敢妄下
·本人任思運中文朗誦比評判,感榮
一、香港的大愿敦育機會週報:: 六十軒被,香港的大帕政爾橋張得太漫,现一項比,從小一至中六學生,亦有帻合接觸,我
開大這個問題的,在原則上那就閲然是肯
[英國的大學傳統,有两點足以打浪香港成立第11
古三的門招現
有良好表現,證明他們禇瓷會經下過一番研究
根雖然摇運......體知堂出美朗確
朗 乽體同觀 誦,有的均
誦有朗一,,而很水成歲,
食了的酒開
雞名 诗句支達
調節
發聖之滑亮科
香
一般印象
100%
的主創術始制 評觀作,
心校
體態及其他
情感之
秦爾富低强弱之控制 節奏都急之適當處理
子之清晰
個人
力 *教指癌注佰節完人饺,體
錢而
「酒都過的每麵。
逃標
練功,除传组人一致的懸記先數 集我的現 型體方眼:很的
外適質!
地卧司材,亦加:
世捨
腐,冠有限霞诚大,
日均軍 附穩容然胴箱以合
到地成,招出客我有現想 賽晚職 客是爲 困 - 一起
出心上冠朱
选人時果筒文旨生在且乘冠銜率文,都安門上 然後,我旣多蛋入不罩。女我說朝一
甲乙丙
【時,則將一欄再到分爲用乙丙丁四級。比賽時
·我個人評定航戰時,忠黨以此爲根蟻
衣遊行,黃惑橋」,但無此評定成體,揭開為命
例的敗判貌舒服,致然
,經交月目
時間
11770英文中學會考試題預習專欄
Example 2 Solve graphically, 5x
81
36.
SOLUTION 5x 8x
堅道英文書院主編
36 = 0
1.
x2 - (8x + 36)
Let y = x
then y- (8x + 36)
數學科
MATHEMATICS (20) ►
· Graphs and Simple Applications
In drawing a graph of the single equation
*= f(x); it is essential that the following rules be obeerved.
(i) After ascertaining the range of values of the corresponding values of y are calculated in tabular form on the ordinary sheet of paper.
(ii) The axes X'OX, Y'Or are now placed on the graph paper so as to use up as much of the graph. pa par; as possible, then positions being determined by the Tangas of values of x and y.
(111) A11 the points on the graph pape "corresponding to the x and y valuem is the calculated: table will be shown by either a dot in a small circle, or by a small cross.
(iv) The point of intersection of the two axis need not be the point where 1 - 0 and 3 m 0. The point is so chosen that as little as possible of the graph paper is wasted.
(v) A line parallel to the long aide of the graph paper can be used for the x-axis, if this be more suitable than the short side.
Intersection of Curves, and Solution of Equations
To find graphically the approximate solutions the equation f(x) = 0, the curva y f(x) is drawn and the points where the curve outs the xmaxie. (ie. at y = 0) will give the required solutions.
In certain onses it is necessary to adopt the
two-graph method or finding the solutions or a given equation, this being particularly the case when the equation f(x)0 can be expressed in the form f(x) = f(x), where f(x) is an algebraical functiony and
non-algebraical function.
In this ease, and also when the curves given by f(x) and fo are well known, the curvas
y = (x) and 3 = f(x) are drawn on the same sheet
and the same. -of graph paper using the aame:axiey
acales of representation for both graphs.
At any
of intersection of the two curves the two values of y will be the same, and therefore at these points 1, (x) » f(x) 1.6. the approximate Bolutions are the values of x at the points of intersection of the two curves.
Example 1▲ orolist starts from A at noon and zides. steadily at 12 m.p.h, towards. B, 60 miles away at 2 p.m. a motorist leaves B for 4 and travels at 36 m.p.h. Find from a graph when the two meet and their distance from A at this time. Find also the times at which they are 12 miles aparts.
x2.6 or -1.6
NOTE: If a Zuration gradually increases (or decreases))
till it reaches a certain value k, which is algebraically greater than (or less than) all neighbouring values on both sides, then k is 7 called a maximum (or minimum) value of the function at the point k
0.g. AB in the fig. the
continuous curve 180
represents the graph of 3- f(x). In which f(x) is a max,at
f(x) is a min, at B
Example 4 without making a table of values, draw rough figures of the graphs of
SOLUTION
+ 5. Which of the done.
2x+50
(b)
0 +1 +2 +3 +4
0 I 49
16
1(8x + 36)
-2 3 4
41213.6
The roots of the given equation, 5x2 - 8x 36, ard the values of which satisfy the above pair of aimultaneous equations. From the graphs as shown. find.
2 or 3.6
NOTE: The above problem can also be solved by drawing
the graph y= 5x - 8x 36. The intersections of the graph and the x-axis (ie. the st. line 70) are the solutions.
Example 3 ray the graph of y (2 + x){3 −x) and find the maximum value of (2 + x)(3-1) Find, also, as accurately as possible, the values of x for which 12 + x)(3 = x) is equal to 2
MSOLUTION.
(0) x
is a para
and y when x
2
no roots
3 = (x-1)° Which is of the same shape aa the graph in (a), but differ by 4 units (An ymaxon)
− 2x + 5 • (x − 1)2
Which is again differ by 4 unite in comparison with(a)
(x − 1)2 + 4
O, the graph of -2x+5 (1.8. graph C) does not cut the x-axis. Hence, no solution for this equation
xample
Dolvo", graphically the following pair of ainiltaneous equations x-3-31 23: 18.
.0
-3
0
+3
+18 +9
+4
+4.5
Their speeds are uniform,...their travel graphs are linear, As found from the graphs:
They meet at 2:45 p.m., 33 miles from i They are 12 mi apart at 2:30 p.m. and at 3 p.m.
y = (2 + x)(3
I -2
2
3
2+
3
I
1
·3. 4 5 22
4 3
2 1
24
y
4 -6. 6 4
-x) 18 0.25
(1) the max. value of (2 + x)(3
11) From the graph, when (2 + x)(3 − x) - 2
From the graphs, the pt. or intersection are (6, 3), (-3, -6) the solutions are
31 Or I...
NOTE: The curve xy- 18 18 known
as a rectangular hyperbola. Any equation of the form
xy`=k} k = const.
will give a similar graph
as in the right hand sid figure.