BO+AĦG237 WAH KIU YAT PO
(ET)
預習題解答
751435-
BZP 2 12 AP-AC TE PD. ZN.
线交
NA..
M
PN=2ND.
一边上之高,骂两腰在斜边上射影
中項)
APAC=√2a)
(ᅀ底边平行线分两腰成比例)
P=Y, AD=
則
气定理)
a-x2
Q.E.D.
↓(畢氏定理)
za2= y2 } ( {xxzq).
zay2
y2 Up y2x2=a+----(1)
+a
32
=a
-(3)
y=a, x=a.
PN 2ND.
Q.E.D
→ * * * * q + fe
嗎
ECD.
+)
(矩形之对比相等)
OE? (畢氏定理)
-(DE+OF2) [$€£}
DE2+ EP2)
EP2 ( 畢氏定理).
-Op (st+*)
OP2 (等量之同倍量)
7
常量,OA半徑亦為常量故 (常量之和或差,仍為常量)
4J 34, MZ CD4 § BMX
AE, OM by 32 ₤ W & KP4.
✈ #71 1) 向為同孤闼心台
N
4.
日橋
2(OC+CA2)=4(CM+0M2)=4CM2+40M=4CMTOA
•.•. 4CM = 2(0C2+ CAa2)-OA =OC2+ 2 CAa2 [BOA=OC]
鈴(2)式 CB 2(CA+OA")-Oc2
4CM3
2CA+OC [ @ $120A=0C/.
CB2(等於同量=量)
2CM=CB(两边開方) (====) 1.7K oc, **** N奌,又联MN, AN AC等线/
A
A OBCE, AN=1BC
XA DOACH, MN || AC
(ᅀ两边中点联线定理)
2. MACN為等腰梯形
(因MA=NC=支口园半径)
3 AN=CM (* ** **#*)
4 CM==BC (###)
22CM=80..
四期星:日九廿月五年九六九一番公年八十二國民華中
英中會考生物科試題
HONG KONG
CERTIFICATE OF EDUCATION EXAMINATION (ENGLISH)
Q.E.D
Q.E.D
6) ABCD為平行四边形,以AB AD总边向形外作正方
* ABHK, AD PQ, q] QK=AC
(知) ABCD 平行四辺形
ABHK, ADP Q Ý Z I JEŹ
(RE) QK=
EAC
(BEA)};j< BAK=90°
1<PAQ=90!
(正方形內角為900)
2. LBAK+LBAD+≤DAQ+LKAQ
....
=360°(周角宠理)
3, 4 BAD+LKAQ == 180° (fit)
* <BAD+ZABC=180′′ (*· ADI|BC)
<行球同側内角玉補
5 ¿KAQ=LABC (+8)
6. BCLAD- AQ (OHH FITH ALLY)
7. AB=AK (***) SL )
8. A A B C E ▲ KAQ ( S, A. S.)
9. QK=AC (XXL)
Q. E.D.
(7) A,B,C三已知奌求以A,B,C笃国心,分别作三园
使 A, B 两园外切而C园則均典A,B两园内切,
eko * 14 to 45)
【作法】 1.奖AB. BC, CA
並將CA.CB延長之 2.14 28AQ, 4ABRIG 分角线使交於口桌
3. 13014 OP LAB B
OQLAC.
4. 以A為心,AP為半作
A园.
5 W/ BŽ~ BP $13 148 @. 5.以cc為心ca為半徒作C
7. A,B,C三园為好求.
(証明)略
R
(註)0奌為△ABCC角之旁心:PQ,R為旁切园之切复..
CQ=CR=S, AP: ·AQ=S-b, BP-BR- S-a.
:
(8)A,B两园外切於P.C园典A园内於Q,而與日园
A tot RE <BAC = 2 ¿PRQ.
(護証如題)
A) 1. ABX13 PET CB 逆延長必過点延長CA
必過Q点
两园相切,联心线必過切复)
2.15 RAROLCR, BIRO
為C园之切线
(於半外端垂直于半径之线切
3. 2QR0=QRgH@@A (3Z to A)
4 =<C=QR $xana (anıÁHAJAQ CÁZ *).
5. <QRO=< (4)
6. 41=42 (': BP-BR,
LQRO,
BAY)
7. LABC=21+22=241 (A$HAFAHAZ 4e)
8. # A B C <BAC+ < ABC + 2 c = 180° (Am) 14.)
1963
BIOLOGY
Time allowed Two hours and thirty minutes
MULTIPLE CHOICE SECTION -
(– in separate book (40 marks) SECTION B (60 marks)
Section B
Attempt any FOUR questions. Each question carries 15 marks
(a) What is digestion? Describe the processes and the paths by which
the products of digestion are transported to the heart.
(b). What is an enzyme? Name THREE enzymes and show what part
each plays in the process of digestion.
(a) By means of large labelled diagrams show the extemal and
internal structure of a named dicotyledonous seed.
(b)
What are the functions of the structures. which you have labelled in the diagrams?
What is meant by vegetative propagation? What are the advantages of this process?
(c) By means of large labelled diagrams illustrate the internal structure
of any named bulb.
(a)List the general characteristics of insects.
(b) (i) Why should the mosquito be killed?
(ii)
State the methods which can be used to control the various stages in the life cycle of the mosquito.
Why should the housefly be killed?
(i)
What is the economic importance of the cabbage white butterfly?
(a) In addition to chlorophyll, state the other essential conarions
for starch production.
Describe an experiment to show that chlorophyll is necessary for the production of starch.
'6 What is anaerobic respiration?
Give an account of an experiment to demonstrate anaeroDIC respiration.
5. (a) List the structural features of a parasitic animal which are adaptations to its mode of life, and. state the purpose of these adaptations.
6.
b) Compare the structures of Spirogyra and bread mould, and point out, wherever possible, the particular functions of these structures, Diagrams of these two organisms should be included in your
answer.
From your experience and observations you have made during your field study answer the following:-
(a) List three animals and three plants which you have studied in a
named habitat..
(b) Describe briefly the ways in which each of these organisins is
adapted to the habitat.
英中會考中史科答案
(續)呂思齊,孔頤
丙組(三題選答一題)
7.試道家老子之各重要主服。
老子啤饨,為道家思想之心。其經博大招斷,實難以下數百字概述,今僅襌其三數要點
• BGF--
浙宇強:「人法地,地法天,天法道,道法自然。」光子於天地萬物之外,別立一個, 「道」你,以您港及中地,攪獨,不受制於何物,而您萬物之。旣法自然,
tractual sim - 305, en Madrid MNR • #