二第張四聘

自三十月五年申戊歷夏

英中會考學數學(一)答案

WAH KIU YAT PO

1968

六期里

日八月六年八六九·公羊七十五國民中

(40)

。歐陽鉈文。

試題額習書润

SUGGESTED Answer

化學科

(十二)

林錦衡·

MATHEMATICS

PAPER 1: Arithmetic z Trigonometr

Section B (60 marks),

複習題卅二

2 yr.

at 4% p. a.

1 @ Let $P. be the sum of money invésrea

The amount at compound interest = .

(測驗六)

$P (1+495

選擇題

Simple "

J

+

=$PC (+42x)

(1) 氯化铁溶液放在那一種器皿中不會

起變化

(9)分解生硫

(6)受空氣氧化生硫

(C)與水作用

(2)複分解生金萤硫化物

(2)氨可用作冷凍劑是因為.

(2)沸點低

(6)熔點低

(C)易液化、

凶極易溶於水

(13)濃硫酸令木料變黑是因為

(2)鎂

(2)生熱燃燒

(6)侵蝕力強

(C)有吸水能力

(4)使水氧化

()

>

the diff between their amount

= $P* { % $? * ( 1 * * * 2)

=$Px(104110

- PX 0.0016

which is $48

Hence.

P = 43 -0.0016

30期

Px0.0016 = ±48

The sum of money is $30 wee

.

.

the gross profit is $2500 the

the net profit is $150mD

-

$50 $20,

M.. Chan's salary = 16% of $20 000 – $ 3200

= $2000 – $3.200 -$16800

The remainder on net profit

Proportion of their investments

Chan : Lee: He m¢tom: $90000: $110 200

Mr. Chas receives: $320+上叶$6800

= $3200 + $480.

8oVY

Mr. Lee recens

receives Mr. Ho

*

£ of $16800 = $ 5400

What the three cyclists be A, B, C.

of which, A's speed is

B's "

C's

16 A.

.

AD

2.2

Ste

(乙)那一種水溶液令石蕊試紙呈藍色

(3)上題結果之決定是彌盧

(Q)氯化鈉

(b)硫酸銨

(C)硝酸銅

(2)碳酸氫鈉

4)電解作用

(6)電離作用

(C)水解作用

(七)中和作用

>

()

(4)溶液加氫氧化鈉溶液生棕色沉澱此

溶液

(4)

(C)

在面四種元素的富子織 何者届過渡性元素

(4) 2,97

(b)2, £,£

(C) 2, 8, 8.

(d) 2,8,9,2

中指

(

()

(14)通二氧化碳於石灰水初生沉澱通過

童反而澄清,因為,

(2)沉澱分鲜

(b)沉澱可溶於酸液

(二)二氧化碳過量反應逆轉 (

()

(d)沉澱再起作用成可溶物

複習題卅一解答

[.(1) Ca(HCC2+ Ne2 CO2 NaHCO + Cało2+, Mg(HCO3)+ Nazcg→2NaHCO3+ NGCOW

Mason+ Na2CO3 → Na2 504+ Mg CO L Calls + Nascl → 2Nacl+ CaClow

皆生白色沉澱

生白色沉澱因氯化銀不溶於硝酸

(3) Cl2+2HI → KCl+ I2

澱粉變深藍色因有元素碘存在

I2 + 2 Na2 S2 Q2 →¿NQIT NQ,Sa

琠受硫代硫酸釻還原石化因

再無元素碘存在澱粉復變無色。

鈉铁 碗/碟

硫氧

質子数!

26

53

6

16

J

中子数

12

30

74

6

電子数

26

53

6

8

比層

2

2

2

2

4 J

$

M層

کی کی عمر

6

N

2

18

7

週期

3

4 5

N

/

4

3

Z

6

何類元素 過渡并非全国非金、非金蜃 非金蛋

Time taken for A to round the track, sc"

B

C

**** 76 Stc.

THE ĜO Séc.

for 11 times

A needs B

"

Go Me Xi}=21315米表

c. of them is

= Coo Ste - ro min

-

344X300

+

6)一般固体化合物對水的溶解度隨溫

度升高而

(Q)增加

(b)減低

(C)不受影响

(四)作不規則的增減

7)在同溫同壓下等容積的任何氣体

(2)重量相等

(b)原子数目相等

(C)分子数

(七)重量成簡單整數比

(8)硬水含有

0

(9)鈣離子

(D)鎂離子!

(無鏃離子

(d)

LIBRARIES

(0) Nat

Na

:

離子鍵

磷當量是

(C) SO2

[ Heroe, the aş'a time is 4 of (2a×3×5°x11)40,

700

The distance from the sun to the earth 18.95 million miles

See

And, the speed of light = 300 millions møber pu

The time

in chia per 120 mallida roviles per so..

taken for the light to traveli

93 32.4 x 300

millions niles

12 X3 X 1760

millions mike për ste....

93 X 12 X 3 X 1750

$7.4 X 300

sec

~ 498.5 sec. (to a tig.

Bei) Radius of the nemisphere = 4.00 CA

Volume

/1

ne

tog 93 1.9685) 12 1.0742 3 04771 1760 3.24IT Mum.6.7763

39.4 1.594 300 2.477/ Pen.4.0726 Exp 12.6972.

' = £ » (4"}3 = £281 c.5.

3

ļ ie the volume of steel is 12 os.

density of steci is

8.19 gm per 6,6. weight of the solid=8.19 gux

) 鈣鎂離子

(a) 3.1

(b) 7.75 (0)6.2

(e) 5

10)氣的漂白作用是

(2)還原作用

(b)氧化作用

(C)置换作用

(4)複分解作用

(

1)硫化氫的水溶液久置表面生黄色薄

膜是因為硫化氫

xx •

O:ㄨㄨ:

(b) CO2

共價鍵

(d) CSz

S:*c*:5

共價及配位鍵

共價鍵

複習題卅二解答

(2) £

(36

(4) C

(5) 2

(7) C

(8) d

(10) b

(R) C

(1/4) C

(19) d

2.19 129

0.9133

2.1074 0.4971.

Num. 3.5170

Exp.

13.0408

And KC bisects AB at Has (ises a prop.)

a FBC is #t. 4

at c

±( 3 1875 DA + i yd 3 x 25 pd = $1871 825 Vot of water in the cool

4:1875205810

NO

By Pythagoras,

+18759 6319

A 1097 gm

(or 1.097 kg)

~ $21.4 cu. nd.

Exp. 12.7 18

+

25

A

The depth of water at the shallow-end » ¿'= 1 yd.

other end = 1 +25 tan 5

=/+2×1875 23.1878 pd,

Sectional area of the swimming pool is

lat HK be the flagstaff.

of height ** Tom HaAME

AK=HK_cot 30°

45

C

From rẻ. – BHK = &K=HK_cat bot

K

kc

from rh a Cilk, CK = HK Cot砾岩

K. A C. B are points on the same hovranial gr.'

is a mexan of isos. A KAB of which KB = KA = √ × H

BC = 1AB - Foji.

Wax)= x* * sot

1

3x=

+250.

2** = 250 o

the height of the flagstaff is 20364.

20, 11) Let & be the centre

of the circle. Join OA OB

4A0B-180-165"=-15′′ Let "be the length of the radius of the circle

✪ of the Chole #271 m

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