有二第張四第

日二十月四年乙春夏

WAH KIU YAT PO

華僑教育

九六五問題預習專欄

物理科

(113)

陸永熾·

11 Solution

(a). To compare the e.m.f.s of two cells using a slide-wire

potentiometer.

Safety

resisto

E

driving ceri

F. and B: cella to be compared

galvanometer

Chliding jockey

G

The positive terminals of £ and C, is connected in turn, through a sensitive centre-zero galvanometer and safety resister to the positive terminal of the potentiometer A. For each cell the position of the contact C along the wire is adjusted until no current flows through the galvanedeter.

and * are the corresponding Tengths of the patientiometer wire for a balance if B, and connected in tura, then

(b) Précautiune takent.

L

(1) Be sure that tlie e.m. f. of the compared

than that of the "drive cell

12) A enfety resistor of 2000 olima or core fliputy he

plused in variea sith the galvanemeter to protect At by limiting the current

Jiffortient the antsty resistor after locating the

Ealance point approximately.

feating effect of a current

The best (1) produced when a current pasans through

wire is proportional to 1

(1) The square of the current (1")

(15)

(is) The rezistance of the vire (H)

(111) The time (t)

Mathematically

(e) thargy given out by the heater

equivalent of cylinder

*mf. gontraind

日二十月五年五六九一楼公年四十五國民高中

ZDE BOE.

Coil horizontal,

Maximum induced~

SE

Coil retating

各位同学

Tovarda vertical

BSE DOE

Col vertical:

no induced current

Current reversed

after vertical, passed

【 英文中學 F1英數科先修專欄 金繼

本欄內容包括以下各點&

Warking of 1 4 geueratür

da the coil rotater its rides rak lenna of force anil therefore, a current isced xh it, when the coils Pu horizontal position in cute, the maximum nuount of vines of furce and the elmefa induced in MAXLANVÉ, keelm, f. induces. ay the coil comes up a vertical: position, a further ratutión vill reverse the direčtřapua of the induced ea In general tue nurrent reverses when the coil pusses the vertical and the current is a mazimusi when the quil fa norizontal, and Tero when it is sertical.

coll horizontal coil vertical

[4] Compare 116, and 1.C.

Potential intrer ense In Wo Lerai 1. 13 always Channe

Potent sof whe terminal 34 Kl980 Preater than the

Current reverses according to Current unirecciona the Entot generation an

éveles per second.

Voltage can be readily chang Transformers do not work ei by means of transformers. I wish DAN

Can be transmitted with ligh" Cannot be traliuma voltage

wigle voltage.

Cannot charge storage batter 198 and electroplating-

Can be use as effeciently or even, more conveniently tuần/ D.C..

Generated by A.C. dynamos and induction: coil,

(0)

(1)

Upel ating lamps, motors, henters, ekos

Generated by batteries. dynumos,

·官先恭祝大家小學都黨。其次,我很高興能够有機會在迴專黶中和大家討論英文革裾科的問題 通常,在英文中學有算術一科,其牌無實際上並不比中學入學試中文算術科課程齬,但由於用 英文作答,是以大家能會稍感困难,尤其是參加學校之入學試,所考內容可能極簡單,但若不懂英 交名翻的運用及題目之分析,則會吃藏 *

有了以上的原因,我希望盡我所能,使大家對於F.1英交算術科的基礎稍為燦固,以償將來邃 取優秀的成績。

一但由於本科的範圍太廣,同時本人對算術的知識有,故在所難免,還望教育界的變數 學家以及各位同學多多指正,原諒。再者,若有任何建類或問題,多多來情,我當會盡力去改善

不過,由於時間所限,不能一路費,在渲我預先請求原諒。

(一)介紹中學入學試其菲科的英文屏障。

(二)英文術名詞的運用。

(三)題目的分析,由淺入深,以便於短期內能解,能做能答

(四)各類題之後,會安排一些有代表性的蟀習,希望各位同學能多話,務求熟能生巧, (五)類似學校入學試的試題會盡量升室。

現在,我首先介紹政育司署頒佈之中學入學試算術科課程範圍的英文解釋:

ARITHMETIC

Mechanical processes and problems involvings The four rules.

Prime and composite numbers; factors and multiples

common factor and lowest common multipla, Use of brackets.

Money Hong Kong, English, and U.S, currencies.

reduction: conversion; shopping exercise, bijis. Vulgar Fractions; reduction to lowest terms; the four ruiBY *ractions of concrete quantities; one quantity saprosess

a fraction of another; simplification.

Decimal Fractionai the four rules; simplifžostjon; BODY.RF119F of decimal fractions into vulgar fractione; conversions of vulgar fractions into decimal fractiona; one quantity expressed as the decimal fraction of another; decimal, actions of concrete quantities (recurring decimaλa excluded).

Simple percentages and easy applications; conversion of

and decimal fractions into percentages,

Simple averages.

Simple interest (without the use of the formula); Measures: reduction and the four rules- Chinese and British

systems commonly used in Hong Kong

(1) Li, cheung, chek, chuen;

miles, Yards, fost, inches;)

(2) piculs, catties, taels;

tons, pounds, ounces:

(3) gallons, pints;

fong cheung, fong chak, fong chuens w

feet, square incheat square yards,

Area and perimeters of squares, rectangles, triangles and

parallograms; radius, diameter and circumference oficircle

being taken as 22/7

Volumes cubes and cuboids: ca

Lap fong chek, lap rong chuen cubic feet, cubic inches.

Unitary Method: direct and inverse proportion; time, work,

distance, etc.

Simple accounts

Simple graphs and diagrams,

For of paperi

The paper will consist of mechanical questions and *.volens the solutions of which will involve operation with Kundi

numbers,

Questions of an objective type will be set and will.

be designed to test réasoning as well as knowledge of

arithmetical processes.

Marginal space will be available pa

[the sight of the questions for working

cylinder sud content

中學入學弑算術科程綱要

包括下列各項之享式演算及文字習題;

154

154 x 454 gm.

Ueat retained by cylinder and content

==.01. bezt produced

• 154 x 454 gu ■ (190055), deg. P. x 1:cal./gm.deg.e 154 × 454 x 135 x ——— cal.

of heat produced -

250

50 × 3 × 3600 - 154 x 454 × 135

Cal:

Secondary turas". Primary turna

Secondary turna

Secondary voltage Primary Voltage 400 x 6.

turns.

Wattage in secondary circuit,

-1.5 amp. x 8 volte

12 valte

80% of the wattage in priienry circuit

Wattage in primary circuit

·2 100

18

·80

15 vatta.

* 135

(4)

FUSE

加減乘除四類。

質數及質因數;約數及倍數;大約是小公告 •

質髅

香港英國及美國之貨幣。

日,貨幣四則合算法:貨幣化法和聚法;港幣點上列外禁之换算法;購物的旁,發票特 分數一約分和部分;分數四則合算法;複名數的分數;分數和麼不防H

雙小數

活$分數化描法。

小數~一小數四則分算法;小数化簡法;化小數認分數,小數和提名數点化法;化分数篇小報

40年德名歡的小數。(循珠小數除外)

慈量習分出及漢易應用題。化分數或小數爲百分數。

雖利法(不必用公式》。

澳量衡——化法,帶法及四期合算法:香港常用之中國制及英制

一、(甲)丈,尺寸:(乙)哞碼呎吋3

二、《甲)缵斤1箱:《乙)噸,礴,安士;

三、加鹽,品麗

四、(甲)方丈,方尺,方寸$

(乙)方确,方呎万吋。

鷗界及面精......一正方形,長方形,三角形及平行四邊形之岗界及面積圓形之半徑,盧在及開

踪。《取河值

22

20.43 ohms

Änergy used in 16 hours -- 250-

Coss of this energy:

20:43 231000

20.43% 1000

250 20.43 (X1000). 5.88 dollars.

16

30 x 0.12)

Solution

(1) A tuple alternate curient generator tian the

following essential parts

(1) Une or more pairs of opposite magnetic pal

neh supply the magnetic field.

(2) An armature, consisting of a coil of wire

would on a soft iron core, and mounted on an axle sa that it can rotate between the field

„Ivo meintlic rings, stip rings, that are

mounted on the armuture" axle and are insulated from each other (one and of the armature a011) 13, attached to sach of the slip rings (4) Two metal or carbon cruakes, mounted so as to

keep in constant contact with one of the slip, ringa

(5) an external circuit consisting of electricni

devices which are to be supplied with current

(i) A2 Tende ( I* * 12

where

amp, Ana

MARJAVI KRUistance of Y. And,

24.0

0.5

480

ohms

1 amp

Wattage of lamp X = 240 †

240 watta'

發精一立方體及長方體:

(电》立方尺,立方寸(乙)上方呎,立方时

歸一法——正比例和反比例*時間工作回應

易部

* 15 22 163 164 •

̇試形式

:包括普通算法及運用蘭溪數目之文宇習題試題,是屬客性的,以歡學生的理解力和

•迷國序的知識,試版右方的空白給學生的算草用。

(本欄逢星期二、三、四、五刊出)

(IV) Cont operate the circuit for 100 hours/

(240 + 60 • 60)

1000

$10.08 And,

x 100 x 0,2813

(v) The 25-watt lamp does not light even if there is short circuit in ons of the these laups as their switches are open

By closing each of the switches independently the short-circuit is located by the observation of the -bril)iance of the 25-vätt lasap./

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